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Refer to the balanced equation. (PLEASE HELP QUICK)

8H2S+8Cl2→S8+16HCl

How many L of chlorine gas, at STP, were required if 2.28 mol reacted?

A) 6.38 x 10^0 L Cl2
B) 1.02 x 10^–1 L Cl2
C) 5.12 x 10^1 L Cl2
D) 4.09x 10^2 L Cl2

Respuesta :

Answer: C) [tex]5.12\times 10^1[/tex] L [tex]Cl_2[/tex]

Explanation: [tex]8H_2S+8Cl_2\rightarrow S_8+16HCl[/tex]

According to Avogadro's law, 1 mole of every gas occupies 22.4 Liters at STP.

Thus from the balanced chemical equation, 8 moles of hydrogen sulfide reacts with 8 moles of chlorine gas.

i.e 8 moles of hydrogen sulfide reacts with [tex]=8\times 22.4L=179.2L[/tex] of chlorine gas.

2.28  moles of hydrogen sulfide reacts with [tex]=\frac{179.2}{8}\times 2.28=51.2L=5.12\times 10^1L[/tex] of chlorine gas.

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