We may start by putting the given equation in slope-intercept from:
[tex]3x-2y = 8 \iff 3x - 8 = 2y \iff y = \dfrac{3}{2}x-4.[/tex]
We can now easily identify the slope:
[tex]m = \dfrac{3}{2}.[/tex]
Since parallel lines have the same slope (as you already seem to know), any line with equation
[tex]y = \dfrac{3}{2} + b, \quad\textrm{with } b \in \mathbb{R},[/tex]
is parallel to the given line. By choosing, for instance, [tex]b = 0[/tex], we get:
[tex]\boxed{y= \dfrac{3}{2}x}.[/tex]
