[tex]\dfrac{12-3y}{2}+\not\!y^1\cdot\dfrac{2y-4}{\not\! y_1}=\dfrac{12-3y}{2}+2y-4\\\\\text{Put the value of y = 3 to the expression:}\\\\\dfrac{12-3(3)}{2}+2(3)-4=\dfrac{12-9}{2}+6-4=\dfrac{3}{2}+6-4=1.5+6-4=3.5[/tex]
The value of expression at y=3 is 19/2 = 9.5
An expression is a mathematical statement consisting of variables , constants , mathematical operators all simultaneously.
The given expression
12-3y/2+y(2y-4/y)
We have to determine the value for for y=3
[tex]\rm 12 - \dfrac{3\times y}{2} +y \times \dfrac{2\times y -4}{y}[/tex]
Putting the value of y = 3
[tex]\rm 12 - \dfrac{3\times 3}{2} +3 \times \dfrac{2\times 3 -4}{3}[/tex]
[tex]\rm 12 - \dfrac{9}{2} +3 \times \dfrac{2}{3}\\\\12 - \dfrac{9}{2} + 2\\\\14-\dfrac{9}{2}\\\\\dfrac{19}{2}[/tex]
Therefore the value of expression at y=3 is 19/2 = 9.5
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