Respuesta :
Answer:
Area of pizza whose longer side is of length is 14 inches = 218.5 [tex]inches^{2}[/tex]
Area of pizza whose longer side of rectangle is 18 inches=258.5 [tex]inches^{2}[/tex]
Area of pizza whose longer side is of length is 29 inches = 368.5 [tex]inches^{2}[/tex]
Step-by-step explanation:
Given A pizzeria makes brick-oven pizzas that are shaped like long rectangles with semi-circles at two ends. The pizzas come in three different sizes, which are measured by the longer side of each rectangle: 14 inches, 18 inches, and 29 inches. All of the pizzas are 10 inches wide, so the semi-circles at the ends have diameters of 10 inches. we have to find the area of each pizza.
First, let us find the area of pizza whose longer side of rectangle is 14 inches
Area of 2 semicircles whose diameter is 10 inches
[tex]=2(\frac{1}{2}\pi r^{2})=\pi r^{2}=3.14\times 5 \times 5 = 78.5 inches^{2}[/tex]
Length = 14 inches
Breadth = 10 inches
Area of rectangle = [tex]length \times breadth[/tex]
= [tex]14\times 10=140 inches^{2}[/tex]
∴ Area of pizza whose longer side is of length is 14 inches = Area of rectangle + area of 2 semicircles
=140+78.5=218.5 [tex]inches^{2}[/tex]
Now, let us find the area of pizza whose longer side of rectangle is 18 inches
Length = 18 inches
Breadth = 10 inches
Area of rectangle = [tex]length \times breadth[/tex]
= [tex]18\times 10=180 inches^{2}[/tex]
∴ Area of pizza whose longer side is of length is 18 inches = Area of rectangle + area of 2 semicircles
=180+78.5=258.5 [tex]inches^{2}[/tex]
Now, let us find the area of pizza whose longer side of rectangle is 29 inches
Length =29 inches
Breadth = 10 inches
Area of rectangle = [tex]length \times breadth[/tex]
= [tex]29\times 10=290 inches^{2}[/tex]
∴ Area of pizza whose longer side is of length is 29 inches = Area of rectangle + area of 2 semicircles
=290+78.5=368.5 [tex]inches^{2}[/tex]
