Answer:
Product of 3y^-4 and 2y^-4 is 6y^-8
Step-by-step explanation:
Given,
3y^-4 and 2y^-4
Product of 3y^-4 and 2y^-4
i.e 3y^-4 * 2y^-4
or 3*2*y^(-4-4)
or 6y^-8
Hence we get product of 3y^-4 and 2y^-4 is 6y^-8