5 g of ammonium nitrate was dissolved in 60 g of water in an insulated container. The temperature at the start of the reaction was 23.0°C and at the end it was 19.0°C. Use the equation below to calculate the energy absorbed by the reaction.

Respuesta :

Answer: 1.00464 kJ of energy is absorbed by the ammonium nitrate from the water.

Explanation:

[tex]NH_4(NO_3)+H_2O\rightarrow NH_4OH+NHO_3[/tex]

Mass of water used in reaction = 60 g

Initial temperature of the water before reaction = 23°C

Final  temperature of the water after temperature = 19°C

Specific heat capacity of water = [tex]4.186J/g^oC[/tex]

Change in temperature =[tex]\Delta T=19^oC-23^oC=-4^oC[/tex]

[tex]Q=mC\Delta T=60 g\times 4.186J/g^oC\times (-4^oC)[/tex]

[tex]Q=-1,004.64 J=-1.00464 kJ[/tex]  (1 kJ = 1000J)

The negative sign means that energy from the water is absorbed by the ammonium nitrate that is this reaction is an  endothermic reaction.

The energy of 1.00464 kJ of energy is absorbed by the ammonium nitrate from the water.