Answer:
The inequality is [tex]8x+17\geq 137[/tex]
Step-by-step explanation:
Given : The isosceles triangle with base and side 4x+3, 2x+7.
And the perimeter is at least 137ft.
To write : An inequality for x
Solution : Let the base [tex]b=4x+3[/tex] and sides [tex]s=2x+7[/tex]
The perimeter of Isosceles triangle is [tex]P=2s+b[/tex]
where s=side and b=base
Now, we have given that perimeter is at least 137 ft.
Therefore, the inequality form is
[tex]2(2x+7)+(4x+3)\geq 137[/tex]
[tex]4x+14+4x+3\geq 137[/tex]
[tex]8x+17\geq 137[/tex]