Answer:
[tex]\frac{-4xy}{x^2-y^2}[/tex] is the answer
Step-by-step explanation:
[tex]\frac{x-y}{x+y} -\frac{x+y}{x-y}[/tex]
making denominator same
[tex]\frac{(x-y)(x-y)}{(x+y)(x-y)} -\frac{(x+y)(x+y)}{(x-y)(x+y)}[/tex]
[tex]\frac{(x^2+y^2-2xy)}{x^2-y^2} -\frac{(x^2+y^2+2xy)}{x^2-y^2}\\\frac{x^2+y^2-2xy-x^2-y^2-2xy}{x^2-y^2}\\\frac{-4xy}{x^2-y^2}[/tex]
