Answer:
Given equation: [tex]x^2+4x =7[/tex]
when we complete the square , we take half of the value of 4 , then square it, and added to the left sides, we get;
[tex]x^2+4x+2^2 = 7+2^2[/tex]
∵4 is the value [tex](\frac{4}{2})^2[/tex]
Notice, that we add this both sides so that it maintains the equality.
then;
[tex]x^2+4x+2^2 = 7+2^2[/tex]
[tex](x+2)^2 = 7+ 4[/tex] [[tex](a+b)^2 = a^2+2ab+b^2[/tex] ]
Simplify:
[tex](x+2)^2 =11[/tex]
Therefore, the equation result is, [tex](x+2)^2 =11[/tex]
Answer:
The resulting equation is (x + 2)^2 = 11
Step-by-step explanation:
It is given that, x^2 + 4x=7 ----(1)
The quadratic equation is of the form ax^2 + bx + c = 0
in completing square method we have to add( b/2)² in both the sides
In eq (1) b = 4, then b/2 = 4/2 = 2
Therefore we have to add 2^2 = 4 in both sides of the eq (1)
eq (1) becomes x^2 + 4x + 4=7 + 4
x^2 + 4x + 4 = 11
(x + 2)^2 = 11
Therefore the resulting equation is
(x + 2)^2 = 11
