PLEASE HELP!!

Let f(x)=8(3)^x^−2 +2 .

The graph of f(x) is stretched vertically by a factor of 3 to form the graph of g(x) .

What is the equation of g(x)?

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Respuesta :

Answer: The equation of g(x) is given by

[tex]g(x)=8(3^{x^{-2}+1}+2)[/tex]

Step-by-step explanation:

Since we have given that

[tex]f(x)=8(3)^x^{-2} +2[/tex]

According to question, the graph of f(x) is stretched vertically by a factor of 3 to form the graph of g(x).

Equation for vertically stretch by a factor of 'a' is given by

[tex]g(x)=a\times f(x)[/tex]

Since there is vertically stretch by a factor of 3 i.e.

[tex]g(x)=3(8(3^{x^{-2}}))+2\\\\g(x)=8(3^{x^{-2}+1}+2)[/tex]

Hence, the equation of g(x) is given by

[tex]g(x)=8(3^{x^{-2}+1}+2)[/tex]