Answer:
option A is correct (i.e. 1/2)
Step-by-step explanation:
It was given that Kristen made 4 out of 5 throws in her first basketball game, 5 out of 8 in her second game and 5 out of 7 free throws in her third game.
We are asked to find the experimental probability of Kristen marking her first free throw in her fourth game.
" As there are only two possibility that the first throw will be free or not ".
Hence the total outcomes=2
Hence, Probability that the throw is free= [tex]\dfrac{1}{2}[/tex]
Hence, 1/2 is the experimental probability of Kristen marking her first free throw in her fourth game.
The experimental probability of Kristen marking her first free throw in her forth game is; A: ½
We are told that;
First game; she made 4 out of 5 throws.
Second game; she made 5 out of 8 throws.
Third Game; she made 5 out of 7 free throws
Now, for the experimental probability of making her first free throw in the fourth game, we know that it's either the first throw is made or not made
Thus;
Experimental probability of making her first throw in her fourth game = ½
Read more about experimental probability at; https://brainly.com/question/8652467
