contestada

A 16.6 kilogram shotput is held 1.3 meters above the ground. What is the gravitational potential energy of the shotput relative to the ground?

Respuesta :

Gravitational Potential energy is given as

[tex]U = mgh[/tex]

here we know that

m = 16.6 kg

h = 1.3 m

now we will have

[tex]U = (16.6)(9.8)(1.3)[/tex]

now we have

[tex]U = 211.5 J[/tex]

so the potential energy will be 211.5 J with respect to ground

onyebuchinnaji

The gravitational potential energy of the shotput relative the ground is 211.48 J.

The given parameters;

  • mass of the shotput, m = 16.6 kg
  • position of the shotput, h = 1.3 m

The gravitational potential energy of the shotput relative the ground is calculated as follows;

P.E = mgh

where;

  • m is the mass of the shotput
  • g is acceleration due to gravity
  • h is the height of the shotput

P.E = 16.6 x 9.8 x 1.3

P.E = 211.48 J

Thus, the gravitational potential energy of the shotput relative the ground is 211.48 J.

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