Answer:
1. Use a compass to make arc marks which intersect above and below then connect.
2. [tex]y=\frac{1}{3}x + 2[/tex]
Step-by-step explanation:
1. To construct a perpendicular line, use a compass to draw arc marks from one end of the segment through point P. Then repeat this again at the other end. This means at point P there will be two intersecting arc marks. Repeat the process down below with the same radius as used above. Then connect the two intersections.
2. The point slope form of a line is [tex](y-y_1)=m(x-x_1)[/tex] where [tex]x_1=-3\\y_1=1[/tex]. We write
[tex](y-1)=m(x--3)\\(y-1)=m(x+3)[/tex]
Since the line is to be perpendicular to the line shown it will have the negative reciprocal to the slope of the function 3x+y =-8. To find m, rearrange the function to be y=-8-3x. The slope is -3 and the negative reciprocal will be 1/3.
[tex](y-1)=\frac{1}{3}(x+3)[/tex]
Simplify for slope intercept form.
[tex](y-1)=\frac{1}{3}(x+3)\\(y-1)=\frac{1}{3}x+1\\y=\frac{1}{3}x + 2[/tex]
