What is the equation of the line graphed below?

Answer:
Option C is correct.
The equation of line graphed is, [tex]y = \frac{1}{2}x[/tex]
Step-by-step explanation:
Point slope form: The straight of line in the form of :
[tex]y-y_1 =m(x-x_1)[/tex] ......[1] where m is the slope.
Consider two points from the given graph:
(0, 0) and (2, 1)
First calculate slope:
Slope(m) = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
Substitute the given values we have;
[tex]m = \frac{1-0}{2-0} = \frac{1}{2}[/tex]
Substitute the given values m and (0,0) in [1] we have;
[tex]y-0 =\frac{1}{2}(x-0)[/tex]
Simplify:
[tex]y = \frac{1}{2}x[/tex]
therefore, the equation of line graphed is, [tex]y = \frac{1}{2}x[/tex]
The equation is passing through (2, 1) and the origin will be y = 1/2 x. Then the correct option is C.
The missing question is attached below.
A linear system is one in which the parameter in the equation has a degree of one. It might have one, two, or even more variables.
The equation of a line is given as
y = mx + c
The equation is passing through the origin, then we have
c = 0
Then the equation will be
y = mx
The equation is passing through (2, 1). Then we have
1 = 2m
m = 1/2
Then the equation will be
y = 1/2 x
Then the correct option is C.
More about the linear system link is given below.
https://brainly.com/question/20379472
#SPJ5