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A car traveling at 22 m/s starts to decelerate steadily. It comes to a complete stop in 5 seconds. What is its acceleration?

Respuesta :

GTjackets09
For uniform acceleration (or deceleration in this case), you use the formula:

Vf = Vi + at

Vi = 22 m/s
Vf = 0 (coming to a stop)
t = 5 sec

Plugging everything into the formula gives you:

0 = 22 + 5a
-22 = 5a
a = -22/5 or -4.4 m/s^2

Hope this helps!

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