to subtract fractions, we need a common denominator.
[tex] \frac{3}{y-2} [/tex] - [tex] \frac{1}{y+3} [/tex]
the common denominator will be (y-2)(y+3)
[tex] \frac{3(y+3)-1(y-2)}{(y-2)(y+3)} [/tex]
[tex] \frac{3y + 9 - y + 2}{(y-2)(y+3)} [/tex]
[tex] \frac{2y + 11}{(y-2)(y+3)} [/tex]
The answer above will be the simplified form.
