A 60 kg Gila monster on a merry-go-round is traveling in a circle with a radius of 3 m, rotating at a rate of 9 revolutions/minute.
(A) What acceleration does the monster experience?

(B) What is the net force?

(C) If the Gila monster crawls inwards to a distance of 1 m from the center, what is the new value of the force the Gila monster experiences?

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aristocles aristocles · Answer 1 · 2019-01-19T03:03:32+01:00

PART A)

mass of the monster = 60 kg

radius = 3 m

frequency = 9 rev/min = 9/60 rev/s

now we can find the angular speed as

[tex]\omega = 2 \pi f[/tex]

[tex]\omega = 2 \pi (9/60) = 0.94 rad/s[/tex]

now the acceleration is given by

[tex]a_c = \omega^2 R[/tex]

[tex]a_c = (0.94)^2(3) = 2.66 m/s^2[/tex]

PART B)

now as per Newton's law we have

[tex]F_c = ma_c[/tex]

from above all values we have

[tex]F_c = 60(2.66) = 159.9 N[/tex]

Part C)

now monster moves inside at radius R = 1 m

so now centripetal acceleration is given as

[tex]a_C = \omega^2 R[/tex]

[tex]a_C = 0.94^2(1) = 0.88 m/s^2[/tex]

now the force experience by monster

[tex]F_C = ma_C[/tex]

[tex]F_c = 60(0.88) = 52.8 N[/tex]