please help ! RT is the perpendicular bisector of SU. Find the value of n and SU.

Answer:
The value of n is 5 and the length of side SU is 4 units.
Step-by-step explanation:
It is given that RT is the perpendicular bisector of SU.
It means RT bisects the line SU and T is the midpoint of SU.
Since T is the midpoint of SU, therefore the distance of T from S and U are same.
[tex]ST=TU[/tex]
[tex]4n-18=32-6n[/tex]
[tex]4n+6n=32+18[/tex]
[tex]10n=50[/tex]
Divide both sides by 10.
[tex]n=5[/tex]
The value of n is 5.
[tex]SU=ST+TU[/tex]
[tex]SU=4n-18+32-6n[/tex]
[tex]SU=-2n+14[/tex]
Put n=5,
[tex]SU=-2(5)+14[/tex]
[tex]SU=4[/tex]
The length of side SU is 4 units.
Answer:
[tex]n=5\text{ and }SU=4\text{ units}[/tex]
Step-by-step explanation:
Given information: RT is the perpendicular bisector of SU, ST=4n-18 and TU=32-6n.
It is given that RT is the perpendicular bisector of SU. It means RT divides SU in two equal parts at T.
[tex]ST=TU[/tex]
Substitute the given values.
[tex]4n-18=32-6n[/tex]
[tex]4n+6n=32+18[/tex]
[tex]10n=50[/tex]
Divided both sides by 10.
[tex]n=5[/tex]
The value of n is 5.
[tex]ST=TU=32-6(n)=32-6(5)=32-30=2[/tex]
We need to find the measure of SU.
[tex]SU=ST+TU[/tex]
[tex]SU=2+2[/tex]
[tex]SU=4[/tex]
Hence, the measure of SU is 4 units.