Respuesta :
efficiency of heat engine is given as
[tex]\eta = 1 - \frac{T_2}{T_1}[/tex]
now we know that
[tex]T_2[/tex] = temperature of sink
[tex]T_1[/tex] = temperature of high temperature source
now it is given that
[tex]T_2 = 50 k[/tex]
[tex]T_1 = 225 k[/tex]
now from the given equation we have
[tex]\eta = 1 - \frac{50}{225}[/tex]
[tex]\eta = 0.78[/tex]
so efficiency of heat engine will be 78%