It takes Zachary’s mother 25 minutes to ride her bike to the market. The market is 1 3/4 miles away. If she rides the same speed to the park that is 10 1/2 miles away, how long will the ride take?

It takes Zacharys mother 25 minutes to ride her bike to the market The market is 1 34 miles away If she rides the same speed to the park that is 10 12 miles awa class=

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Answer:

option D is correct

time will the ride take = 150 minutes

Step-by-step explanation:

Using formula:

[tex]\text{Speed} = \frac{\text{Distance}}{\text{Time}}[/tex]            .....[1]

As per the given condition:

Zachary's mother take time to rider her bike to the market = 25 minutes.

and the distance of the market away = [tex]1\frac{3}{4} = \frac{7}{4}[/tex] miles.

Then, substitute these value in [1] , we have;

[tex]\text{Speed} = \frac{\frac{7}{4}}{25} =\frac{7}{4 \times 25} = \frac{7}{100}[/tex] miles per minutes.

It is also given that , if she rides with the same speed to the park that is [tex]10\frac{1}{2}= \frac{21}{2} \text{miles}[/tex] away.

To find how long will the ride take.

Using the same formula to find the time;

Let the time be t.

we have;

[tex]\frac{7}{100} =\frac{\frac{21}{2}}{t}[/tex]

By cross multiply, we have;

[tex]7t = \frac{21}{2} \times 100[/tex]

Simplify:

[tex]7t = 1050[/tex]

Divide by 7 both sides we get;

t = 150 minutes.

Therefore, 150 minutes will the ride take.


Answer:

option-D

Step-by-step explanation:

Case-1:

It takes Zachary’s mother 25 minutes to ride her bike to the market

and that market is [tex]1\frac{3}{4} =1.75miles[/tex] away

so, distance =d=1.75 miles

time =t= 25 minutes

so, firstly we can find speed

[tex]v=\frac{d}{t}[/tex]

[tex]v=\frac{1.75}{25}[/tex]

[tex]v=0.07miles/min[/tex]

Case-2:

Since, speed is same

so,

[tex]v=0.07miles/min[/tex]

Distance is

[tex]=10\frac{1}{2}=10.5miles[/tex]

so,

[tex]d=10.5miles[/tex]

now, we can find time

[tex]t=\frac{d}{v}[/tex]

we can plug values

[tex]t=\frac{10.5}{0.07}[/tex]

[tex]t=150min[/tex]

She will take 150 minutes