It takes Zachary’s mother 25 minutes to ride her bike to the market. The market is 1 3/4 miles away. If she rides the same speed to the park that is 10 1/2 miles away, how long will the ride take?

Answer:
option D is correct
time will the ride take = 150 minutes
Step-by-step explanation:
Using formula:
[tex]\text{Speed} = \frac{\text{Distance}}{\text{Time}}[/tex] .....[1]
As per the given condition:
Zachary's mother take time to rider her bike to the market = 25 minutes.
and the distance of the market away = [tex]1\frac{3}{4} = \frac{7}{4}[/tex] miles.
Then, substitute these value in [1] , we have;
[tex]\text{Speed} = \frac{\frac{7}{4}}{25} =\frac{7}{4 \times 25} = \frac{7}{100}[/tex] miles per minutes.
It is also given that , if she rides with the same speed to the park that is [tex]10\frac{1}{2}= \frac{21}{2} \text{miles}[/tex] away.
To find how long will the ride take.
Using the same formula to find the time;
Let the time be t.
we have;
[tex]\frac{7}{100} =\frac{\frac{21}{2}}{t}[/tex]
By cross multiply, we have;
[tex]7t = \frac{21}{2} \times 100[/tex]
Simplify:
[tex]7t = 1050[/tex]
Divide by 7 both sides we get;
t = 150 minutes.
Therefore, 150 minutes will the ride take.
Answer:
option-D
Step-by-step explanation:
Case-1:
It takes Zachary’s mother 25 minutes to ride her bike to the market
and that market is [tex]1\frac{3}{4} =1.75miles[/tex] away
so, distance =d=1.75 miles
time =t= 25 minutes
so, firstly we can find speed
[tex]v=\frac{d}{t}[/tex]
[tex]v=\frac{1.75}{25}[/tex]
[tex]v=0.07miles/min[/tex]
Case-2:
Since, speed is same
so,
[tex]v=0.07miles/min[/tex]
Distance is
[tex]=10\frac{1}{2}=10.5miles[/tex]
so,
[tex]d=10.5miles[/tex]
now, we can find time
[tex]t=\frac{d}{v}[/tex]
we can plug values
[tex]t=\frac{10.5}{0.07}[/tex]
[tex]t=150min[/tex]
She will take 150 minutes