Segment AC is a diameter of circle P, which has a radius 13 cm. If B is a point on circle P such that AB = 10 cm, what is the length of segment BC?

Respuesta :

Answer:

Length of segment BC = 24 cm

Step-by-step explanation:

It is given that AC is a diameter and B is a point on the circle P.

So, Δ ABC is a triangle in a semicircle and hence ∠ B = 90° as angle in a semicircle is a right angle.

It is also given that the length of the radius is 13 cm.

Therefore, diameter AC = 2 × radius = 2(13) = 26 cm.

It is given that AB = 10 cm.

From the right triangle Δ ABC,

[tex]AC^{2} =AB^{2} +BC^{2}[/tex]

[tex]26^{2} =10^{2} +BC^{2}[/tex]

[tex]BC^{2}=26^{2} -10^{2}[/tex]

[tex]BC^{2}=576[/tex]

BC = 24 cm