Answer:
Energy bar B has the highest rate of sugar to fiber.
Step-by-step explanation:
For energy bar A, the rate is [tex]\frac{14}{12}[/tex] = [tex]\frac{7}{6}[/tex]
For energy bar b, the rate is [tex]\frac{10}{8}[/tex] = [tex]\frac{5}{4}[/tex]
For energy bar C, the rate is [tex]\frac{9}{9}[/tex]
Now,
The least common multiple of 4 and 6 is 12.
So, we can write
[tex]\frac{7}{6} =\frac{14}{12}[/tex]
[tex]\frac{5}{4} =\frac{15}{12}[/tex] and
[tex]\frac{9}{9} =\frac{12}{12}[/tex]
From the above information, we can easily find that energy bar B has the highest rate of sugar to fiber.
