Answer:
A. [tex]x+y=6...(1)[/tex]
[tex]20x+15y=100...(2)[/tex]
B. Yes, Pablo can buy 2 pair of pants and 4 shirts.
Step-by-step explanation:
A. Let x be the number of pairs of pants and y be the number of shirts.
We have been given that Pablo wants to purchase 6 additional clothing pieces for his wardrobe. We can represent this information as:
[tex]x+y=6...(1)[/tex]
We are also told that each pair of pants costs $20 and each shirt costs $15. So the cost of x pairs of pants will be 20x and cost of y shirts will be 15y.
As Pablo wants to spend $100 on clothing, so we can represent this information as:
[tex]20x+15y=100...(2)[/tex]
Therefore, the system of equation representing the given situation will be:
[tex]x+y=6...(1)[/tex]
[tex]20x+15y=100...(2)[/tex]
B. To find if Pablo can buy 2 pair of pants and 4 shirts we will substitute x=2 and y=4 in our both equations.
[tex]2+4=6[/tex]
[tex]6=6[/tex]
[tex]20*2+15*4=100[/tex]
[tex]40+60=100[/tex]
[tex]100=100[/tex]
We can see that x=2 and y=4 satisfies our both equation, therefore, Pablo can buy 2 pair of pants and 4 shirts.
