Respuesta :
Here we have to get the effect of addition of 0.25 moles of gas C on the mole fraction of gas A in a mixture of gas having constant pressure.
On addition of 0.25 moles of C gas, the mole fraction of gas A will be [tex]\frac{moles of gas A}{moles of gas A + 0.25}[/tex].
The partial pressure of gas A can be written as [tex]P_{A}[/tex] = [tex]x_{A}[/tex]×P (where [tex]x_{A}[/tex] is the mole fraction of gas A present in the mixture and P is the total pressure of the mixture.
The mole fraction of gas A in a mixture of gas A and C is = [tex]\frac{moles of gas A}{moles of gas A + moles of gas C}[/tex] and [tex]\frac{moles of gas C}{moles of gas A + moles of gas C}[/tex] respectively.
Thus on addition of 0.25 moles of C gas, the mole fraction of gas A will be [tex]\frac{moles of gas A}{moles of gas A + 0.25}[/tex].
Which is different from the initial state.
