The numbers that are the solutions to [tex]-\frac{3}{4}x+2\frac{1}{4} = (\frac{1}{2})^x+1[/tex] are -1 and 1
The functions are given as:
- [tex]f(x) = -\frac{3}{4}x+2\frac{1}{4} [/tex].
- [tex]g(x)= (\frac{1}{2})^x+1[/tex].
See attachment for the graphs of f(x) and g(x).
From attached graph, both functions intersect at x = -1 and x = 1
This means that:
- 1 and 1 represent the solutions to [tex]-\frac{3}{4}x+2\frac{1}{4} = (\frac{1}{2})^x+1[/tex]
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