Answer:
[tex]y=\frac{5}{7}x[/tex] and [tex]y=\frac{7}{9}x[/tex]
Step-by-step explanation:
A simple way to solve this problem is to plug the corresponding x and y into the function. We need only one pair since all the functions are quasi-linear (y=kx) and the increase is proportional.
In [tex]y=\frac{5}{7}x[/tex] when x=3, y=15/4≈2.14
In [tex]y=\frac{3}{5}x[/tex] when x=3, y=1.8
In [tex]y=\frac{7}{9}x[/tex] when x=3, y≈2.33
In [tex]y=\frac{7}{11}x[/tex] when x=3, y≈1.90
We can observe that in two cases, [tex]y=\frac{5}{7}x[/tex] and [tex]y=\frac{7}{9}x[/tex], y is greater than 2.
