A car travels down a road at a certain velocity, vcar. The driver slows down so that the car is traveling only half as fast as before. Which of the following is the correct expression for the resulting velocity?

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Answer:

The expression for the resulting velocity is, [tex]-\frac{1}{2}V_ \text{car}[/tex]

Step-by-step explanation:

As per the given statement: A car travels down a road at a certain velocity,[tex]V_\text{car}[/tex]

Let initial velocity of car travel downward= [tex]-V_\text{car}[/tex]

It is also, given that the driver slows down so that the car is traveling only half as fast as before.

⇒Resulting velocity = [tex]-\frac{1}{2}V_ \text{car}[/tex]

Therefore, the expression for the resulting velocity is, [tex]-\frac{1}{2}V_ \text{car}[/tex]