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Two bags both contain blue marbles and green marbles. Bag A contains 6 blue marbles and 4 green marbles and Bag B contains 2 blue marbles and 3 green marbles. A marble is drawn from each bag. What is the probability that both marbles are green?

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absor201

Answer:

6/25

Step-by-step explanation:

Total marbles in Bag A = 6 blue + 4 green = 10 marbles.

Total marbles in Bag B = 2 blue + 3 green = 5 marbles.

P(Green marble is drawn from Bag A) = Green Marbles/Total Marbles = 4/10.

P(Green marble is drawn from Bag B) = Green Marbles/Total Marbles = 3/5.

Assuming that both the above probabilities are independent, therefore:

P(Both marbles are green) = 4/10 * 3/5 = 12/50 = 6/25.

Hence, the probability is 6/25!!!

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