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gmany

[tex]\left\{\begin{array}{ccc}-x+2y+z=10\\z=6\\3x-2y+2z=8\end{array}\right\\\\\text{Put the value of z to the first and the second equation:}\\\\\left\{\begin{array}{ccc}-x+2y+6\\3x-2y+2(6)=8\end{array}\right\\\\\left\{\begin{array}{ccc}-x+2y+6=10&|\text{subtract 6 from both sides}\\3x-2y+2(6)=8\end{array}\right\\\\\left\{\begin{array}{ccc}-x+2y=4\\3x-2y+12=8&|\text{subtract 12 from both sides}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-x+2y=4\\3x-2y=-4\end{array}\right}\qquad\text{add both sides of the equations}[/tex]

[tex].\qquad2x=0\qquad\text{divide both sides by 2}\\.\qquad\boxed{x=0}\\\\\text{Put the value of x to the first equation:}\\\\-0+2y=4\\2y=4\qquad\text{divide both sides by 2}\\\boxed{y=2}\\\\Answer:\ \boxed{x=0,\ y=2,\ z=6\to(0,\ 2,\ 6)}[/tex]

Answer:

(0,2,6)

Step-by-step explanation:

-x+2y +z=10

z=6

3x-2y+2z=8

We know z   so substitute it in

-x +2y +6 =10

Subtract 6 from each side

-x+2y +6-6 =10-6

-x +2y = 4

3x-2y+2(6)=8

3x-2y +12 =8

Subtract 12 from each side

3x-2y+12-12 = 8-12

3x-2y =-4

Add these two equations

-x +2y = 4

3x-2y =-4

-----------------------

2x = 0

Divide by 2

2x/2 = 0/2

x =0

Now we need to find y

-x +2y = 4

0+2y =4

Divide by 2

2y/2 = 4/2

y=2