A rubber ball with a mass 0.20 kg is dropped vertically from a height of 1.5 m above the floor. The ball bounces off of the floor, and during the bounce 0.60 J of energy is dissipated. What is the maximum height of the ball after the bounce?

Potential Energy = mass * Hight * acceleration of gravity
PE=hmg
PE = 1.5 * .2 * 9.81
PE = 2.943
it lost .6 so 2.943 - .6 = 2.343
now your new energy is 2.343 so solve for height
2.343 = mhg
2.334 = .2 * h * 9.81
h = 1.194
the ball after the bounce only went up 1.194m

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snehashish65 snehashish65 · Answer 2 · 2021-11-13T13:23:59+01:00

The maximum height achieved by the ball is 0.306 m.

Given data:

The mass of rubber ball is, m = 0.20 kg.

The height is, h = 1.5 m.

The energy dissipation is, E = 0.60 J.

When the ball bounces off to achieve a height (h), then the energy dissipation will take place in the form of potential energy. Then,

Energy dissipated = Potential energy

E = PE

E = mgh

Here, h is the maximum height

[tex]E = mgh\\\\0.60 = 0.20 \times 9.8 \times h \\\\h = 0.306 \;\rm m[/tex]

Thus, we can conclude that the maximum height achieved by the ball is 0.306 m.

learn more about the energy dissipation and potential energy here:

https://brainly.com/question/17858145