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How many pieces 3 and three fifths in. long can be cut from 28 metal rods each 15 in.​ long? Disregard waste.

Respuesta :

Answer: 112 pieces


Step-by-step explanation:

1. Rewrite [tex]3^{\frac{3}{5}}[/tex] as a decimal. Divide the numerator and the denominator of the fractional part and add it to the integer part:

[tex]3+0.6=3.6in[/tex]

2. You know that each metal rod is 15 inches long. Then, you must divide the lenght of each one by 3.6:

[tex]pieces=\frac{15in}{3.6in}4.16[/tex]

3. The waste is 0.16, therefore, you obtain 4 pieces from a metal rod. The total pieces obtained from 28 metal rods are:

[tex]total=4pieces*28=112pieces[/tex]

Answer:

116 whole pieces

Step-by-step explanation:

We have a 28 metal rods that are 15 inches long each, out of which we need to cut [tex]3\frac{3}{5}[/tex] inches long metal rods.

Firstly, we will convert the mix fraction into improper fraction and then divide the total length of the rod by it.

[tex]3\frac{3}{5}[/tex] inches = [tex]\frac{18}{5}[/tex] inches

Dividing the total length of rod by this length and multiplying it by 28 to get:

[tex]\frac{15}{\frac{18}{5} }[/tex] = [tex]28 (15 * \frac{5}{18})[/tex] = [tex]116.6[/tex]

Therefore, 116 whole pieces can be cut from the given length of rod.