Answer: [tex]y=3sin(\frac{5}{2}x)[/tex]
Step-by-step explanation:
1. You know the following equation of sine function:
[tex]y=Asin(B(x+C))+D[/tex]
2. Where:
A is the amplitude.
[tex]B=\frac{2\pi}{period}[/tex]
C is phase shift and D is vertifcal shift
3. C and D are zero. Then:
[tex]A=3\\B=\frac{2\pi}{\frac{4\pi}{5}}=\frac{5}{2}[/tex]
4. Substitute these values into the equation:
[tex]y=3sin(\frac{5}{2}x)[/tex]
