Answer: [tex]5=log_{2}(32)[/tex]
Step-by-step explanation:
1. By definition, you have if [tex]y=b^{x}[/tex], then [tex]x=log_{b}(y)[/tex]
2. Keeping this on mind, you must follow the proccedure shown below:
- You have that:
[tex]2^{5}=32[/tex]
Where:
[tex]x=5\\y=32\\b=2[/tex]
- Substitute values into [tex]x=log_{b}(y)[/tex]. Then, you obtain:
[tex]5=log_{2}(32)[/tex]
Answer:
5 = log₂ 32
Step-by-step explanation:
When a logarithmic equation is written as b = logₐ c
That means its exponential form is aᵇ = c
In this question exponential expression is given as 2⁵ = 32
By comparing with exponential form given above we find a = 2, b = 5 and c = 32
Now we put these values in the logarithmic equation
5 = log₂ 32 will be the logarithmic equation.