derek found a function that approximately models the population of iguanas in a reptile garden, where x represents the number of year since the iguanas were introduced into the garden

i(x) = 12(1.9)^x

Rewrite this function in a form that reveals the monthly grow rate of the population of iguanas in the garden. Round the growth factor to the nearest thousandth

Respuesta :

Answer:

Monthly growth function is [tex]i(x)=12 \times (1+\frac{0.9}{12})^{12x}[/tex] and growth rate is 0.075.

Step-by-step explanation:

We are given,

The function which models the population of iguanas in a reptile garden is [tex]i(x)=12 \times 1.9^{x}[/tex], where x is the number of years.

As, [tex]i(x)=12 \times 1.9^{x}[/tex]

i.e. [tex]i(x)=12 \times (1+0.9)^{x}[/tex]

So, the monthly growth rate function becomes,

[tex]i(x)=12 \times (1+\frac{0.9}{12})^{x \times 12}[/tex]

i.e. [tex]i(x)=12 \times (1+\frac{0.9}{12})^{12x}[/tex].

Hence, the monthly growth rate population of iguanas is i.e. [tex]i(x)=12 \times (1+\frac{0.9}{12})^{12x}[/tex].

Moreover, the growth factor is [tex]\frac{0.9}{12}[/tex] = 0.075.

Hence, the growth factor rounded to nearest thousandth is 0.075

the answer is i(x)12x(1+0.9/12)^12x