How many moles of calcium chloride (CaCl2) are needed to react completely with 6.2 moles of silver nitrate (AgNO3)? 2AgNO3 + CaCl2 → 2AgCl + Ca(NO3)2

A. 2.2 mol CaCl2

B. 3.1 mol CaCl2

C. 6.2 mol CaCl2

D. 12.4 mol CaCl2

Respuesta :

Here we have to choose the right option which tells the moles of CaCl₂ will react with 6.2 moles of AgNO₃ in the reaction

2AgNO₃ + CaCl₂→ 2AgCl + Ca(NO₃)₂

6.2 moles of silver nitrate (AgNO₃) will react with B. 3.1 moles of calcium chloride (CaCl₂).

From the reaction: 2AgNO₃ + CaCl₂→ 2AgCl + Ca(NO₃)₂

Thus 2 moles of AgNO₃ reacts with 1 mole of CaCl₂

Henceforth, 6.2 moles of AgNO₃ reacts with [tex]\frac{6.2}{2}[/tex] = 3.1 moles of CaCl₂.

1 mole of CaCl₂ reacts with 2 moles of AgNO₃. Thus-

A. 2.2 moles of CaCl₂ will react with 2.2×2 = 4.4 moles of AgNO₃.

C. 6.2 moles of CaCl₂ will reacts with 6.2×2 = 12.4 moles of AgNO₃.

D. 12.4 moles of CaCl₂ will reacts with 12.4 × 2 = 24.8 moles of AgNO₃

Thus the right answer is 6.2 moles of AgNO₃ will react with 3.1 moles of CaCl₂.

For the complete reaction of 6.2 moles of Silver nitrate, 3.1 moles of Calcium chloride has been needed.

The balanced chemical reaction can be as follows:

[tex]\rm 2\;AgNO_3\;+\;CaCl_2\;\rightarrow\;2\;AgCl\;Ca(NO_3)_2[/tex]

From the reaction, it is clear that 2 moles of silver nitrate require 1 mole of calcium chloride, for complete utilization.

If 2 moles of silver nitrate has been utilized by 1 mole of calcium chloride, then 6.2 moles of silver nitrate requires:

2 moles Silver nitrate = 1 mole Calcium chloride

6.2 moles Silver nitrate = [tex]\rm \dfrac{1}{2}\;\times\;6.2[/tex] moles Calcium chloride

6.2 moles Silver nitrate = 3.1 moles of Calcium chloride

For the complete reaction of 6.2 moles of Silver nitrate, 3.1 moles of Calcium chloride has been needed.

For more information about the Moles of a compound, refer to the link:

https://brainly.com/question/22804641