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Which of the following is a valid mole ratio from the balanced equation 2Fe2O3 + 3C → 4Fe + 3CO2?

A. four moles of C over three moles of F e

B. two moles of F e two O three over four moles of C

C. three moles of C over four moles of C O two

D. four moles of F e over three moles of C O two

Respuesta :

Answer:

D. four moles of F e over three moles of C O two

Explanation:

I legit took the exam, used this answer: "B. two moles of F e two O three over four moles of C" and got it wrong. If you go to other Q/A sites, google, research, or do anything of the sort you will find conflicting answers. My advicce is do the math and check it if you don't believe me. All I can tell yoi is that this: Four moles of "Fe" over three moles of C O two-- IS THE RIGHT ANSWER. All I ask in return is that you 5 star this when you inevitably get it right. I don't want anyone else to get this wrong, that would suck.

From the given balanced equation, the valid mole ratio is Four moles of Fe over 3 moles of [tex]\rm CO_2[/tex].

Mole ratio can be defined as the ratio of mole compound with the another.

The stoichiometry gives the idea about the moles of compounds in the reaction. The balanced reaction is as follows:

[tex]\rm 2\;FeCO_3\;+3\;C\;\rightarrow\;4\;Fe\;+3\;CO_2[/tex]

  • The mole ratio of Fe to C will be:

Mole ratio of Fe:C = [tex]\rm \dfrac{moles\;of\;Fe}{moles\;of\;C}[/tex]

Mole ratio of Fe : C = [tex]\rm \dfrac{4}{3}[/tex]

Mole ratio of Fe:C = 4 : 3

Four moles of Fe over 3 moles of C.

  • The mole ratio of C to Fe will be:

Mole ratio of C : Fe = [tex]\rm \dfrac{moles\;of\;C}{moles\;of\;Fe}[/tex]

Mole ratio of C : Fe = [tex]\rm \dfrac{3}{4}[/tex]

Mole ratio of C : Fe = 3 : 4.

Three moles of C over 4moles of Fe.

  • The mole ratio of C to [tex]\rm CO_2[/tex] will be:

Mole ratio of C : [tex]\rm CO_2[/tex] = [tex]\rm \dfrac{moles\;of\;C}{moles\;of\;CO_2}[/tex]

Mole ratio of C : [tex]\rm CO_2[/tex] = [tex]\rm \dfrac{3}{3}[/tex]

Mole ratio of C  : [tex]\rm CO_2[/tex] = 1 : 1

1 mole of C over 1 mole of  [tex]\rm CO_2[/tex].

  • The mole ratio of Fe over [tex]\rm CO_2[/tex] will be:

Mole ratio of Fe : [tex]\rm CO_2[/tex] = [tex]\rm \dfrac{moles\;of\;Fe}{moles\;of\;CO_2}[/tex]

Mole ratio of Fe : [tex]\rm CO_2[/tex] = [tex]\rm \dfrac{4}{3}[/tex]

Mole ratio of Fe : [tex]\rm CO_2[/tex] = 4 : 3

Four moles of Fe over 3 moles of  [tex]\rm CO_2[/tex].

From the given balanced equation, the valid mole ratio is Four moles of Fe over 3 moles of [tex]\rm CO_2[/tex].

For more information about the mole ratio, refer to the link:

https://brainly.com/question/14698548

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