Respuesta :
We solve:
[tex] \frac{3}{5} = \frac{12y}{number \: of \: silver \: guppies} \: or \\ \\ 3 \times (number \: of \: silver \: guppies) \: \\ = 60y \\ \\ this \: means \: the \: number \: of \: \\ silver \: guppies \: in \: terms \: of \: y \: is \: \\ \frac{60y}{3} = 20y [/tex]
[tex] \frac{3}{5} = \frac{12y}{number \: of \: silver \: guppies} \: or \\ \\ 3 \times (number \: of \: silver \: guppies) \: \\ = 60y \\ \\ this \: means \: the \: number \: of \: \\ silver \: guppies \: in \: terms \: of \: y \: is \: \\ \frac{60y}{3} = 20y [/tex]