Respuesta :

AlbertThomas
Let f(q)
[tex] = \frac{ {q}^{2} - 3q - 4}{ {q}^{2} - 7q - 8} = \frac{(q - 4)(q + 1)}{(q - 8)(q + 1)} \\ \\ [/tex]

This means q cannot be 8 or -1
but the discontinuity at -1 can
be removed by redefining f(-1)
abidemiokin

The domain restriction is the point where q is -1 and 8

Given the function [tex]\frac{q^2-3q-4}{q^2-7q-8}[/tex]

The point where the function has a domain restriction is the point where the denominator is 0 as shown:

[tex]q^2-7q-8=0[/tex]

Factorize the resulting function

[tex]q^2-8q+q-8=0\\q(q-8)+1(q-8)=0\\(q+1)(q-8)=0\\q=-1 \ and \ 8[/tex]

Hence the domain restriction is the point where q is -1 and 8

Learn more here: https://brainly.com/question/20624946

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