Answer:
The tire pressure drops to 2.65 atm.
Step-by-step explanation:
Volume remains constant, so we can use Gay-Lussac’s Law.
p₁/T₁ = p₂/T₂ Multiply both sides by T₂
p₂ = p₁ × T₂/T₁
Data:
p₁ = 3.00 atm; T₁ = 30.0 °C
p₂ = ?; T₂ = -5 °C
Calculations:
(a) Convert the temperatures to kelvins
T₁ = 30.0 + 273.15 = 303.15 K
T₂ = -5 + 273.15 = 268.15 K
(b) Calculate the new pressure
p₂ = 3.00 × 268.15/303.15
p₂ = 3.00 × 0.8845
p₂ = 2.65 atm
The pressure drops to 2.65 atm.
