Answer:
No, Han is not correct.
Step-by-step explanation:
In order to question the reasoning of Han, we can start by solving this equation.
6x - 4 + 2(5x + 2) = 16x
Collecting the like terms together and the constant together, we will obtain:
6x + 10x - 16x = 4 - 4
0 *x = 0
This equation has got infinitely many solutions that whatever number you put to the place of x, you will always have zero.
So that, Han's reasoning was not correct.
Answer:
No, I don't agree with Han because there are infinitely many solutions to the equation.
Step-by-step explanation:
We have been given an equation [tex]6x-4+2(5x+2)=16x[/tex]. Han said, “I can tell right away there are no solutions, because on the left side, you will have [tex]6x+10x[/tex] and a bunch of constants, but you have just [tex]16x[/tex] on the right side.”
We are asked to determine whether Han is right or not.
First of all, we will simplify left side of our given equation as:
[tex]6x-4+2\cdot 5x+2\cdot 2=16x[/tex]
[tex]6x-4+10x+4=16x[/tex]
[tex]6x+10x+4-4=16x[/tex]
[tex]16x=16x[/tex]
Since both sides of equation are equal, so any value of x will make the equation true.
Therefore, there will be infinitely many solution of the equation.
