An air balloon begins it's decent to the ground at 1000 ft above the ground and falls at a rate of 50 ft per minute. Select all that apply to this situation.

The slope is 1000 ft per minute. The balloon is falling at 1000 ft per minute.

The y-intercept is 50 ft. The balloon falls at a rate of 50 ft per minute.

The y-intercept is 1000 ft. The balloon begins to from an initial height of 1000 ft.


The slope is -50 ft per minute. The balloon is falling at 50 ft per minute.

It will take the balloon 20 minutes to reach the ground.





















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Answer:

The correct options are 3, 4 and 5.

Step-by-step explanation:

It is given that an air balloon begins it's decent to the ground at 1000 ft above the ground and falls at a rate of 50 ft per minute.

It means the initial height of air balloon is 1000. So, the y-intercept is (0,1000).

The ball falls at a rate of 50 ft per minute. So, the rate of change is

[tex]m=-50[/tex]

The height of balloon is defined as

[tex]h(x)=-50x+1000[/tex]                      [tex][\because y=mx+b][/tex]

Where, x is time in minutes.

The balloon will reach the ground when h(x)=0

[tex]0=-50x+1000[/tex]

[tex]50x=1000[/tex]

[tex]x=20[/tex]

Therefore the options 3, 4 and 5 are correct.