Refer to the following Diagram to answer this question In the Diagram,if the lightbulb is placed at D and B is closed( As shown) What will happen.

When light bulb is placed at the position of D and switch B is closed
So here the circuit is closed and there will be current flow through the circuit
So here we can use ohm's law
[tex]V = iR[/tex]
here we have
V = voltage of battery
R = resistance of bulb
so we will got the current "i" in the circuit
so now we will have power across the bulb as
[tex]P = V i[/tex]
[tex]P = V(\frac{V}{R})[/tex]
[tex]P = \frac{V^2}{R}[/tex]
so bulb will glow with the power we got in above expression after connecting into the circuit