Answer:
Part 1)
The slope is [tex]4[/tex] ft per second since this is how fast the puppy is running
The puppy will run into the wall after [tex]5[/tex] seconds
Part 2) [tex](2,-6.5)[/tex]
Part 3) [tex]rose\ bush: \$6 ; ivy: \$10[/tex]
Step-by-step explanation:
Part 1)
Let
x------> the time in seconds
y-----> the distance in feet
we know that
The linear equation that represent the distance that the puppy runs is equal to
[tex]y=4x[/tex]
the slope is equal to [tex]m=4\frac{ft}{sec}[/tex]
For [tex]x=5\ sec[/tex]
[tex]y=4(5)=20\ ft[/tex]
so
For [tex]x>5\ sec[/tex] -------> the puppy will run into the wall
therefore
The statements that are true are the following
The slope is [tex]4[/tex] ft per second since this is how fast the puppy is running
The puppy will run into the wall after [tex]5[/tex] seconds
Part 2)
we know that
The solution of the system of equations is the intersection point both graphs
In this problem
The x-coordinate of the intersection point is equal to [tex]x=2[/tex]
The y-coordinate of the intersection point belong to the interval----> [tex](-6,-6.5)[/tex]
therefore
the best estimate for the solution to the system is the point [tex](2,-6.5)[/tex]
Part 3)
Let
x-------> the cost of one rose bush
y------> the cost of one pot ivy
z------> the cost of one bush
we know that
[tex]3z+3y=42[/tex] ------> equation A
[tex]3x+3y=48[/tex] ------> equation B
There is not enough information to solve the system of equations
so
Verify the values of each case in the equation B
case A) [tex]rose\ bush: \$7 ; ivy: \$4[/tex]
[tex]3(7)+3(4)=48[/tex]
[tex]33=48[/tex] ------> is not true
case B) [tex]rose\ bush: \$5 ; ivy: \$7[/tex]
[tex]3(5)+3(7)=48[/tex]
[tex]36=48[/tex] ------> is not true
case C) [tex]rose\ bush: \$3 ; ivy: \$5[/tex]
[tex]3(3)+3(5)=48[/tex]
[tex]24=48[/tex] ------> is not true
case D) [tex]rose\ bush: \$6 ; ivy: \$10[/tex]
[tex]3(6)+3(10)=48[/tex]
[tex]48=48[/tex] ------> is true
therefore
The case D is the solution