Respuesta :
Explanation:
According to law of conservation of mass, mass of reactants will be equal to the mass of products, that is, mass can neither be created nor it can be destroyed. As it can only be transformed from one form to another.
So, when 46 grams of Na and 71 grams of [tex]Cl_{2}[/tex] combine together then it results in the formation of NaCl.
The total mass of NaCl formed will be 46 g + 71 g = 117 g
Thus, we can conclude that total mass of NaCl produced is 117 g.
Answer : The total mass of NaCl produced, 80 grams
Explanation : Given,
Mass of Na = 46 g
Mass of [tex]Cl_2[/tex] = 71 g
Molar mass of Na = 23 g/mole
Molar mass of [tex]Cl_2[/tex] = 71 g/mole
First we have to calculate the moles of [tex]Na[/tex] and [tex]Cl_2[/tex].
[tex]\text{Moles of }Na=\frac{\text{Mass of }Na}{\text{Molar mass of }Na}=\frac{46g}{23g/mole}=2moles[/tex]
[tex]\text{Moles of }Cl_2=\frac{\text{Mass of }Cl_2}{\text{Molar mass of }Cl_2}=\frac{71g}{71g/mole}=1mole[/tex]
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
[tex]2Na+Cl_2\rightarrow 2NaCl[/tex]
From the balanced reaction we conclude that
As, 2 moles of [tex]Na[/tex] react with 1 mole of [tex]Cl_2[/tex]
In this reaction, there is no limiting reagent and excess reagent.
Now we have to calculate the moles of NaCl.
From the balanced reaction we conclude that,
2 moles of [tex]Na[/tex] react to give 2 moles of [tex]NaCl[/tex]
Now we have to calculate the mass of NaCl.
[tex]\text{Mass of }NaCl=\text{Moles of }NaCl\times \text{Molar mass of }NaCl[/tex]
[tex]\text{Mass of }NaCl=(2mole)\times (40g/mole)=80g[/tex]
Therefore, the total mass of NaCl produced, 80 grams
