As we know from work energy theorem that work done by external force is change in kinetic energy
So from all above we can say
[tex]W = k_f - K_i[/tex]
in order to find work done we can say
[tex]W = F.d[/tex]
here we have
[tex]F = 5 N[/tex]
[tex]d = 2 m[/tex]
so we will have
[tex]W = (5)(2) J[/tex]
[tex]W = 10 J[/tex]
so from above equation we can say that final kinetic energy will be same as work done
so we will have kinetic energy as
[tex]K = 10 J[/tex]