Respuesta :
Explanation:
The given data is as follows.
[tex]V_{1}[/tex] = 5.00 L, [tex]V_{2}[/tex] = ?
[tex]T_{1}[/tex] = -50.0 + 273 = 223 K, [tex]T_{2}[/tex] = 100.0 + 273 = 373 K
P = constant
Therefore, calculate [tex]V_{2}[/tex] as follows.
[tex]\frac{PV_{1}}{T_{1}}[/tex] = [tex]\frac{PV_{2}}{T_{2}}[/tex]
Since pressure is constant so, P will be cancelled out from both the sides.
[tex]\frac{V_{1}}{T_{1}}[/tex] = [tex]\frac{V_{2}}{T_{2}}[/tex]
[tex]V_{2}[/tex] = [tex]\frac{V_{1}T_{2}}{T_{1}}[/tex]
= [tex]\frac{5.00 L \times 373 K}{223 K}[/tex]
= [tex]\frac{1865 L}{223}[/tex]
= 8.36 L
Thus, we can conclude that [tex]V_{2}[/tex] is 8.36 L.
