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PLEASE HELP!!! A.S.A.P!!

The Pythagorean Theorem,
Right Triangles Trigonometry

The park department rents canoes at docks near each entrance to the park. To the nearest meter, how far is it from one dock to the other?

A.) 207 m



B.) 142 m



C.) 160 m



D.) 63 m

PLEASE HELP ASAPThe Pythagorean TheoremRight Triangles TrigonometryThe park department rents canoes at docks near each entrance to the park To the nearest meter class=

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RanTam

Answer:

142m

Step-by-step explanation:

This problem can be solved by simply using the pythagorean theorem, as you stated at the beginning of the problem, which is: [tex]a^{2} +b^{2} =c^{2}[/tex]

You are given the a side and b side that are needed for this equation, so it's all a matter of plugging in the information you have:

[tex]110^{2} +90^{2} =c^{2}[/tex]

[tex]110^{2} =12100[/tex]

[tex]90^{2} =8100[/tex]

[tex]12100+8100=c^{2}[/tex]

[tex]20200=c^{2}[/tex]

Now, because the c is still squared, you must take the square root of 20200 in order to get the length of just side c:

[tex]\sqrt{20200}[/tex]≈142m

The square root of 20200 in order to get the length of just side [tex]$c$[/tex] is [tex]142 \mathrm{~m}$[/tex].

This problem can be solved by simply using the Pythagorean theorem, as you stated at the beginning of the problem, which is: [tex]$a^{2}+b^{2}=c^{2}$[/tex]

You are given the [tex]$a$[/tex] side and [tex]$b$[/tex] side that are needed for this equation, so it's all a matter of plugging in the information you have:

[tex]110^{2}+90^{2}=c^{2}[/tex]

[tex]&110^{2}=12100 \\[/tex]

[tex]&90^{2}=8100[/tex]

[tex]&12100+8100=c^{2} \\[/tex]

[tex]&20200=c^{2}[/tex]

Now, because the [tex]$c$[/tex] is still squared, you must take the square root of 20200 in order to get the length of just side [tex]$c$[/tex] :

[tex]\sqrt{20200} \approx 142 \mathrm{~m}$[/tex].

Learn more about  the square root of 20200 in order to get the length of just the side [tex]$c$[/tex]

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