A sled of mass 10 kg slides along the ice. it has an initial speed of 2 m/s but stops because of friction. How much work is done by friction?

A. 0 J
B. -20 J
C. -10 J
D. 20 J

Respuesta :

Answer: The correct answer is option B.

Explanation:

Mass of the sled = 10 kg

Initial speed of the sled = 2 m/s

Kinetic energy of the sled = [tex]\frac{1}{2}mv^2[/tex]

[tex]\frac{1}{2}\times 10 kg\times (2 m/s)^2=20 Joules[/tex]

Work done by the sled = 20 joules

The work done by the friction will be in opposite direction and equal to the magnitude of the work done of the sled that - 20 J.

Hence, correct answer is option B.

Answer:-20

Explanation: