I need help pls!! Can someone help me

Answer:
[tex]\large\boxed{41.74\ m^2}[/tex]
Step-by-step explanation:
We have the rectangle in the base and two pairs of the triangles.
The rectangle:
[tex]A_r=(4.8)(3.8)=18.24\ m^2[/tex]
The triangle 1:
[tex]A_{t1}=\dfrac{1}{2}(4.8)(2.6)=6.24\ m^2[/tex]
The triangle 2:
[tex]A_{t2}=\dfrac{1}{2}(3.8)(2.9)=5.51\ m^2[/tex]
The Surface Area of the rectangular pyramid:
[tex]S.A.=A_r+2A_{t1}+2A_{t2}\\\\S.A.=18.24+2\cdot6.24+2\cdot5.51=41.74\ m^2[/tex]