Respuesta :
Answer: 47.04 L will be the volume occupied by the 2.1 moles of nitrogen gas at STP.
Explanation:
At STP,
1 mol of ideal gas occupies = 22.4 L
Considering nitrogen gas to be an ideal gas
Then 2.1 moles of the nitrogen gas will occupy:
[tex]2.1 \times 22.4 L= 47.04 L[/tex]
47.04 L will be the volume occupied by the 2.1 moles of nitrogen gas at STP.
